2sin^2x-3cosx=3

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Solution for 2sin^2x-3cosx=3 equation:


Simplifying
2sin2x + -3cosx = 3

Reorder the terms:
-3cosx + 2in2sx = 3

Solving
-3cosx + 2in2sx = 3

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
-3cosx + 2in2sx + -2in2sx = 3 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
-3cosx + 0 = 3 + -2in2sx
-3cosx = 3 + -2in2sx

Divide each side by '-3osx'.
c = -1o-1s-1x-1 + 0.6666666667in2o-1

Simplifying
c = -1o-1s-1x-1 + 0.6666666667in2o-1

Reorder the terms:
c = 0.6666666667in2o-1 + -1o-1s-1x-1

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